failinggirll failinggirll
  • 01-10-2021
  • Mathematics
contestada

Find four consecutive integers such that the sum of the first three is 18 more than the fourth.

Respuesta :

AlgebraicAardvark
AlgebraicAardvark AlgebraicAardvark
  • 01-10-2021

If x is the first integer, then

x+1 is the second,

x+2 is the third, and

x+3 is the fourth.

Now we need those to be such that adding the first three equals the fourth plus 18.

     x + x+1 + x+2 = x+3 + 18

Solving that equation, we'd do:

    3x + 3 = x + 21

          2x = 18

            x = 9

That means 9 is the first integer, so the others are 10, 11, and 12.

Answer Link

Otras preguntas

What are the 4 main products for southeast
How did the alliances that formed in Europe after world war 2 form an "iron curtain" as described by Winston Churchill in a 1946 speech?
2 friends want to equally share 4/3 feet of rope.What length of rope should ea friend get?
Use trig to solve for x show work
how does the carbon cycle work in the desert
Use the order of operations and the digits 2,4,6 and 8 to create an expression with a value of 2
What is the slope of (2,3) , (6,7)
the length of a rectangle is 3 feet less than twice the width of the rectangle. if the perimeter of the rectangle is 324 feet, find the width and the length?
how do you now 11/33 is a simplest form
SAT Help Jack can paint a house in 5 days, and Richard can paint the same house in 7 days. Working together, how long will it take them to finish the job? How d