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In a set of 12 devices 4 are defective. Assume that all of the defective and all of the functional devices are indistinguishable. How many linear orderings are there in which no two defective devices are consecutive

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aliakbar921853

Answer: 126 orderings

Step-by-step explanation:

Here let's suppose that total devices is given by n= 12

and defective ones are given by m= 4

Now, to find the number of orderings in which no two defective devices are consecutive is given by following relation.

Ā¹Ā²ā»ā“āŗĀ¹ā‚„C

= ā¹ā‚„C

= 126 orderings

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