Answer:
1st box ā perpendicular
2nd box ā B and E
3rd box ā congruent
Step-by-step explanation:
* Lets revise the case SAS of similarity
- SAS similarity : In two triangles, if two sets of corresponding sides Ā
Ā Ā are proportional and the included angles are equal then the two Ā
Ā Ā triangles are similar.
- Example : In triangle ABC and DEF, if mā A = mā D and Ā
Ā AB/DE = AC/DF then the two triangles are similar by SAS
* Lets solve the problem
- In Ī ABC and Ī DEF
āµ AB/DE = BC/EF = 1/2
- That means two sets of corresponding sides are proportion
āµ AB is a vertical side and BC is a horizontal side
āµ DE is a vertical side and EF is a horizontal side
āµ Horizontal and vertical lines are perpendicular
ā“ AB ā„ BC and DE ā„ EF
- So angles B and E are right angles by definition of perpendicular
Ā Ā lines
āµ All right angles are congruent
ā“ mā B = mā D
āµ The two triangles have two sets of corresponding sides are
Ā proportion and the included angles are equal then the two
Ā Ā triangles are similar
ā“ ā³ABC ~ ā³DEF by the SAS similarity theorem