Shclark2020
Shclark2020 Shclark2020
  • 04-06-2018
  • Mathematics
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simplify the complex function (n-3/n^2+6n+8)/(n+1/n+2)

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jdoe0001 jdoe0001
  • 04-06-2018
[tex]\bf \cfrac{\quad \frac{n-3}{n^2+6n+8}\quad }{\frac{n+1}{n+2}}\implies \cfrac{\quad \frac{n-3}{(n+4)(n+2)}\quad }{\frac{n+1}{n+2}}\implies \cfrac{n-3}{(n+4)\underline{(n+2)}}\cdot \cfrac{\underline{n+2}}{n+1} \\\\\\ \cfrac{n-3}{(n+4)(n+1)}\implies \cfrac{n-3}{n^2+5n+4}[/tex]
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